Question

A capacitor of `10 muF` stores charge 10 mC at given potential difference. If capacitace of capacitor is double then find charge shared for same potential difference.

Answer 1

`(C_(1))/(C_(2)) = (Q_(1))/(Q_(2))`
`Q_(2) = (C_(2))/(C_(1)) xx Q_(1)`.
`= 20mC`