Here, `m_(1) = 1kg, u_(1)= 10m//s , m_(2) 5kg u_(2) = 0`
Before impact, total momentum `= m_(1)u_(1)+m_(2)u_(2)`
or `P_(1) = 1xx10+5xx0 = 10kg m//s`
just after impact, total momentum remains the same, i.e.,
`P_(2)=P_(1)=10 kg m//s`
If v is velocity of the combined object,
then from `P_(2)= (m_(1)+m_(2))v, v=p_(2)/(m_(1)+m_(2))= 10/((1+5))= 1.67 m//s`