Question

A hammer of mass `500g`, moving at `50m//s`, strikes a nail. The nail stops the hammer in a very short time of `0.01 s`. What is the force of the nail on the hammer?

Answer 1

Here,`m=500g = (500)/(1000)kg= 0.5kg, u=50m//s,v=0, t=0.01 s`
clearly, `F=ma =(m(v-u))/t = (0.5(0-50))/(0.01)= -2500N`
Negative sign indicates the opposing force.