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Find the manitude of a charge whose electric field strength is `18 xx 10^(3) N C^(-1)` at a distance of 5 m in air .

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Electric field strength `E = 18.2 xx 10^(-6) N C^(-1)`
Charge of an electron `e = 1.6 xx 10^(-19)C`
Mass of an electron `m = 9.1 xx 10^(-31) kg`
`E = F/q`
`F = Eq = 18.2xx 10^(-6) xx 1.6 xx 10^(-19)`
But `F = ma`
`:. 9.1 xx 10^(-31) xx a = 18.2 xx 10^(-6) xx 1.6 xx 10^(-19)`

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