Question

A truck of mass `M` is moved under a force `F`. If the truck is then loaded with an object equal to the mass of the truck and the driving force is halved, then how does the acceleration change?

Answer 1

As mass of loaded truck becomes 2 times and driving force is halved, therefore, from
`F=ma, a=F/m=(1//2 "time")/(2 "time")=1/4` time
i.e., acceleration would become `1/4th`