Let the given points be A(-5,6) B(3,0) and C(9,8).
Therefore, AB = BC = 10 units
This show that \(\triangle ABC\) is right angled at B.
Therefore, the points A(-5,6) B(3,0) and C(9,8) are the vertices of an isosceles rightangled triangle
Also, area of a triangle = \(\frac{1}{2}\times base\times height\)
If AB is the height and BC is the base,
\(Area=\frac{1}{2}\times 10\times 10\)
= 50 square units