The total number of outcomes = 80.
Let E1 be the event of getting a perfect square number.
Out of these number perfect square number are 1, 4, 9, 16, 25, 36, 49, and 64.
Thus, the number of favorable outcomes = 8
Therefore, P(getting a perfect square number) = P(E1) = \(\frac{number\, of \,outcomes\,favorable\,to\,E_1}{number\,of \,all\,possible\,outcomes} \) = \(\frac{8}{80}\) = \(\frac{1}{10}\).
Thus, the probability tht the disc bears a perfect square number is \(\frac{1}{10}\).