Number of 50-p coins = 100.
Number of 1 coins = 70.
Number of 2 coins = 50.
Number of 5 coins = 30.
Thus, total number of outcomes = 250.
(i) Let E1 be the event of getting a Rs. 1 coin.
The number of favorable outcomes = 70.
Therefore, P(getting a Rs. 1 coin) = P(E1) = \(\frac{number\, of \,outcomes\,favorable\,to\,E_1}{number\,of \,all\,possible\,outcomes} \) = \(\frac{70}{250}\) = \(\frac{7}{25}\)
Thus, the probability that the coin will be a Rs. 1 coin is \(\frac{7}{25}\)
(ii) Let E2 be the event of not getting a Rs. 5
Number of favorable outcomes = 250 - 30 = 220
Therefore, P( not getting a Rs. 5 coin) = P(E2) = \(\frac{number\, of \,outcomes\,favorable\,to\,E_2}{number\,of \,all\,possible\,outcomes} \) = \(\frac{220}{250}\) = \(\frac{22}{25}\)
Thus, probability that the coin will not be a Rs. 5 coin is \(\frac{22}{25}\).
(iii) Let E3 be the event of getting a 50-p or a Rs 2 coins.
Number of favorable outcomes = 100 + 50 = 150
Therefore, P(getting a a 50-p or a Rs 2 coin) P(E3) = \(\frac{number\, of \,outcomes\,favorable\,to\,E_3}{number\,of \,all\,possible\,outcomes} \) = \(\frac{150}{250}\) = \(\frac{3}{5}\)
Thus, probability that the coin will be a 50-p or a Rs 2 coin is \(\frac{3}{5}\).