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in Science by (50 points)
. Two masses m1 and m2 are suspended together by a massless spring of spring constant k as shown in Fig. 2. When the masses are in equilibrium, m1 is removed without disturbing the system. Find the angular frequency and amplitude of oscillation. (5 marks)

Figure 2

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If only mass m2 ​ is present the extension of spring l is given by m2g=kl

⇒l= m2g/k ​ , where k=Spring constant 

Now with m1 ​ and m2 ​ the extension be l ′ (m1 ​ +m2 )g=kl ′

l ′ = (m1 ​ +m2/k)g-m2g/k

⇒ A = m1g/k

Now, if m2 ​ is removed the angular frequency of oscillation ω= \(\sqrt{\frac{k}{m_2}}\) ​ ​ (This is same as the case of m2 ​ attach to spring)

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