Total number of all possible outcomes = 52

There are 26 red cards (including 2 queen) and apart from these, there are 2 more queens.

number of cards, each one of which is either a red card or a queen = 26 + 2 = 28

Let E be the event that the card drawn is neither a red card nor a queen.

Then. the number of favorable outcomes = (52 - 28) = 24

Therefore, P(getting neither a red card nor a queen) = P(E) = \(\frac{24}{52}\) = \(\frac{6}{13}\)