A leap year has 366 days with 52 weeks and 2 days.
Now, 52 weeks contains 52 Sundays.
The remaining two days can be.
(i) Sunday and Monday
(ii) Monday and Tuesday
(iii) Tuesday and Wednesday
(iv) Wednesday and Thursday
(v) Thursday and Friday
(vi) Friday and Saturday
(vii) Saturday and Sunday
out of these 7 cases, there are two cases favorable it to be Sunday
Therefore, P(a leap year having 53 Sundays) = \(\frac{number\, of\,favorable\,outcomes}{number\,of \,all\,possible\,outcomes}\) = \(\frac{2}7\)
Thus, the probability that a leap year selected at random will contain 53 Sunday is \(\frac{2}7\).
