Question

If A(-1,0), B(5,-2) and C(8,2) are the vertices of △ABC then its centroid is 

(a) (12,0) 

(b) (6,0) 

(c) (0,6) 

(d) (4,0)

Answer 1

Correct answer is (d) (4,0)

The given point are A(-1,0), B(5,-2) and C(8,2).

Here, (x₁ = -1,y₁ = 0),(x₂ = 5,y₂ = -2) and (x₃ = 8,y₃ = 2)

Let G(x,y) be the centroid of \(\triangle ABC.\) Then,

Hence, the centroid of \(\triangle ABC\) is G(4,0).