(i) Given: A ⊆ B
Need to prove: A × C ⊆ B × C
Let us consider, (x, y)∈(A × C)
That means, x∈A and y∈C
Here given, A ⊆ B
That means, x will surely be in the set B as A is the subset of B and x∈A.
So, we can write x∈B
Therefore, x∈B and y∈C
⇒ (x, y)∈(B × C)
Hence, we can surely conclude that,
A × C ⊆ B × C [Proved]
(ii) Given: A ⊆ B and C ⊆ D
Need to prove: A × C ⊆ B × D
Let us consider, (x, y)∈(A × C)
That means, x∈A and y∈C
Here given, A ⊆ B and C ⊆ D
So, we can say, x∈B and y∈D (x, y)∈(B × D)
Therefore, we can say that, A × C ⊆ B × D [Proved]