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Evaluate the following limit : \(\lim\limits_{\text x \to 2}\cfrac{\text x^3+3\text x^2-9\text x-2}{\text x^3 - \text x-6} \)

lim(x→2) (x3 + 3x2 - 9x - 2)/(x3 - x - 6)

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Since the form is indeterminant

\(=\cfrac00\)

Method 1: factorization

\(\lim\limits_{\text x \to 2}\cfrac{\text x^3+3\text x^2-9\text x-2}{\text x^3 - \text x-6} \)

By long division method

Since a3 - b3 = (a - b) (a2 + b2 + ab) & a- b2 = (a + b) (a - b)

Method2: By L hospital rule:

Differentiating numerator and denominator separately:

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