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Find the sum (i^n+ i^n+1 + i^n+2 + i^n+3), where n N.

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Find the sum (in+ in+1 + in+2 + in+3), where n N.

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We have in+ in+1 + in+2 + in+3

= in+ in .i + in .i2 + in .i3

= in (1+ i +i2 + i3)

= in(1 + i -1 –i)

= in (0) = 0

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