Given \(\lim\limits_{\text x \to 3}\cfrac{\text x-3}{\sqrt{\text x-2}-\sqrt{4-\text x}} \)
To find: the limit of the given equation when x tends to 3
Substituting x as 3, we get an indeterminant form of \(\cfrac00\)
Rationalizing the given equation
Formula: (a + b) (a - b) = a2 - b2
Now we can see that the indeterminant form is removed, so substituting x as 3
We get \(\lim\limits_{\text x \to 3}\cfrac{\text x-3}{\sqrt{\text x-2}-\sqrt{4-\text x}} \) = \(\cfrac{1+1}2\) = 1