We have seen that the shaded region and origin are on the same side of the line 3x + 4y = 12.
For (0,0) we have 0 + 0 - 12 < 0. So the shaded region satisfies the inequality 3x + 4y \(\le\)12.
We have seen that the shaded region and origin are on the same side of the line 4x + 3y =12
For (0,0) we have 0 + 0 -12 < 0. So the shaded region satisfies the inequality 4x + 3y \(\le\)12.
Also , the region lies in the first quadrent Therefore x \(\ge\) 0 and y \(\ge\)0
Thus the linear inequation comprising the given solution set are +4y \(\le\)12, 4x + 3y \(\le\) 12, x \(\ge\) 0, y \(\ge\)0