Let the number of tables and chairs be x and y respectively.
Therefore x \(\ge\)0, y \(\ge\) 0
Now the maximum number of pieces he can store = 60.
Therefore, x + y \(\le\) 60…….(1)
Also it is given that maximum amount he can invest = 30000
Therefore, 1500 x + 300y \(\le\) 30000 …… (2)
Therefore , the shaded protion (i.e. A) together with its boundary represents the solution set of the given inequation.
No. of tables = x = 10
No. of chair = y = 50