(i) -2x > 5, x є Z
Multiply both the sides by -1 in above equation,
-2x(-1) > 5(-1)
2x < -5
Dividing both the sides by 2 in above equation,
\(\frac{2x}{2} < \frac{-5}{2}\)
x < \(\frac{-5}{2}\)
x < 2.5
Since, x is an integer
Therefore, possible values of x can be
X = {....., -2, -1,0,1,2}
(ii) -2x > 5, x є R
Multiply both the sides by -1 in above equation,
-2x(-1) > 5(-1)
2x < -5
Dividing both the sides by 2 in above equation,
\(\frac{2x}{2} < \frac{-5}{2}\)
x < \(\frac{-5}{2}\)
Therefore,
x ∈(-∞, \(\frac{-5}{2}\)\(\big)\)
x ∈(-∞, \(\frac{-5}{2}\)\(\big)\)