\(\frac{\big(2{\text{x}}-1\big)}{3}\)\(\ge\) \(\frac{\big(3{\text{x}}-2\big)}{4}\) - \(\frac{\big(2-{\text{x}}\big)}{5}\), where x ϵ R.
Multiplying by 60 on both the sides in the above equation.
\((60)\frac{\big(2{\text{x}}-1\big)}{3}\)\(\ge\) \((60)\frac{\big(3{\text{x}}-2\big)}{4}\) - (60)\(\frac{\big(2-{\text{x}}\big)}{5}\)
20(2x – 1) ≥ 15(3x – 2) -12(2 – x)
40x – 20 ≥ 45x – 30 – 24 + 12x
40x – 20 ≥ 57x – 54
Now, Adding 20 on both the sides in the above equation
40x – 20 + 20 ≥ 57x – 54 + 20
40x ≥ 57x – 34
Now, subtracting 57x from both the sides in the above equation
40x – 57x ≥ 57x – 34 – 57x
-17x ≥ -34
Multiplying by -1 on both sides in the above equation
(-17x)(-1) ≥ (-34)(-1)
17x ≤ 34
Now, divide by 17 on both sides in the above equation
\(\frac{17{\text{x}}}{17}\)\(\le\) \(\frac{34}{17}\)
Therefore,
x ≤ 2