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Evaluate: \((i^{41}+\frac{1}{i^{71}})\)

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We have, \((i^{41}+\frac{1}{i^{71}})\)

i41 = i40 . i = i

i71 = i68 . i3 = -i


Hence, \((i^{41}+\frac{1}{i^{71}})\) = 2i

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