Given:
Area of the triangle = 60cm2
Let the sides of the triangle be a, b and c, where a is the height, b is the base and c is hypotenuse of the triangle.
a - b = 7 cm
a = 7 + b ........(1)
Area of triangle = \(\frac{1}{2}\times b\times h\)
Side of a triangle cannot be negative.
Therefore, b = 8 cm.
Substituting the value of b = 8 cm, in equation (1):
a = 7 + 8 = 15 cm
Now, a = 15 cm, b = 8cm
Now, in the given right triangle, we have to find third side.
So, the third side is 17 cm.
Perimeter of a triangle = a + b + c.
Therefore, required perimeter of the triangle 15 + 8 + 17 = 40 cm