Question

Each side of an equilateral triangle is 10 cm. Find 

(i) the area of the triangle and 

(ii) the height of the triangle.

Answer 1

(i) The area of the equilateral triangle = \(\frac{\sqrt{3}}{4}\times side^2\)

= \(\frac{\sqrt{3}}{4}\times 10^2\)

= \(\frac{\sqrt{3}}4{}\times 100\)

= \(25\sqrt{3}\) cm²

Or 25 x 1.732 = 43.3 cm²

(ii) As, area of the equilateral triangle = \(25\sqrt{3}\) cm²

Or height = 5 x 1.732 = 8.66

\(\therefore\) The height of the triangle is \(5\sqrt{3}\) cm or 8.66 cm.