(i)
There are 6 even places and 6 vowels out of which 2 are of 1 kind, 3 are of the 2nd kind
The vowels can be arranged in = \(\frac{6!}{2!3!}\) = 60
There are 6 consonants out of which 2 is of one kind
Number of permutations = \(\frac{6!}{2!}\) = 360
⇒ Total number of words = 360 x 60 = 21600
(ii)
There are 6 vowels to arrange in \(\frac{6!}{2!3!}\)
There are 6 consonants which can be arranged in \(\frac{6!}{2!}\)
⇒ Total number of ways = \(\frac{6!}{2!3!}\times\frac{6!}{2!}\) = 21600