Given: radius = 8 cm
Height = 6 cm
Area = ?
In a right angled triangle, the center of the circumference is the midpoint of the hypotenuse.
Hypotenuse = 2 x (radius of circumference) for a right triangle
= 2 x 8
= 16 cm
So, hypotenuse = 16 cm
Now, base = 16 cm and height = 6 cm
Area of the triangle = \(\frac{1}{2}\times base \times height\)
= \(\frac{1}{2}\times 16 \times 6\)
= 48 cm2