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in Perimeter and Area of Plane Figures by (30.3k points)
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Find the area of a right – angled triangle, the radius of whose, circumference measures 8 cm and the altitude drawn to the hypotenuse measures 6 cm.

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Given: radius = 8 cm

Height = 6 cm

Area = ?

In a right angled triangle, the center of the circumference is the midpoint of the hypotenuse.

Hypotenuse = 2 x (radius of circumference) for a right triangle

= 2 x 8

= 16 cm

So, hypotenuse = 16 cm 

Now, base = 16 cm and height = 6 cm

Area of the triangle = \(\frac{1}{2}\times base \times height\)

\(\frac{1}{2}\times 16 \times 6\)

= 48 cm2

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