Given:
Base = 80 cm
Area = 360 cm2
Area of an isosceles triangle = \((\frac{1}{4}b\sqrt{4a^2-b^2})\)
Squaring both the sides, we get:
\(\Rightarrow\) 81 = a2 - 1600
\(\Rightarrow\) a2 = 1681
\(\Rightarrow\) a = 41 cm
Perimeter = (2a + b)
= [2(41)+80] = 82 + 80 = 162 cm
So, the perimeter of the triangle is 162 cm.