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in Derivatives by (47.4k points)
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If \(y=\cfrac{1+\frac{1}{x^2}}{1-\frac{1}{x^2}},\) then dy/dx =

A. \(-\frac{4x}{(x^2-1)^2}\)

B. \(-\frac{4x}{x^2-1}\)

C. \(\frac{1-x^2}{4x}\)

D. \(\frac{4x}{x^2-1}\)

1 Answer

+1 vote
by (45.0k points)
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Best answer

To calculate dy/dx, we can use the quotient rule.

From quotient rule we know that :

Clearly, from above solution we can say that option (a) is the only correct answer.

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