Question

Each of the equal sides of an isosceles triangle measure 2 cm more than its height, and the base of the triangle measure 12 cm. Find the area of the triangle.

Answer 1

Let the height of the triangle be h cm.

Each of the equal sides measures a = (h + 2) cm and b = 12 cm (base)

Now, 

Area of the triangle = Area of the isosceles triangle

On squaring both the sides, we get:

Area of the triangle = \(\frac{1}{2}\times b\times h\)

= \(\frac{1}{2}\times 12\times 8\)

= 48 cm²