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In how many ways can 8 persons be seated at a round table so that all shall not have the same neighbour in any two arrangement?

1 Answer

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Best answer

By using the formula (n-1)!

So 8 persons can be arranged by 7! 

Now each person have the same neighbour in the clockwise and anticlockwise arrangement 

Total number of arrangement are (7!)/2 = 2520

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