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If \(\frac{1}{4!} +\frac{1}{5!} = \frac{x}{6!}\), find the value of x.

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To Find: Value of n

Given: \(\frac{1}{4!} +\frac{1}{5!} = \frac{x}{6!}\) 

Formula Used: n! = (n) × (n-1) × (n-2) × (n-3) ………. 3 × 2 × 1

Now, \(\frac{1}{4!} +\frac{1}{5!} = \frac{x}{6!}\) 

⇒ \(\frac{1}{24} +\frac{1}{120} = \frac{x}{720}\) (4! = 24, 5! = 120)

⇒ \(\frac{5+1}{120}=\frac{x}{720}\)

⇒ \(\frac{6}{120}=\frac{x}{720}\)

⇒ x = 36

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