To Find: Value of n
Given: \(\frac{1}{4!} +\frac{1}{5!} = \frac{x}{6!}\)
Formula Used: n! = (n) × (n-1) × (n-2) × (n-3) ………. 3 × 2 × 1
Now, \(\frac{1}{4!} +\frac{1}{5!} = \frac{x}{6!}\)
⇒ \(\frac{1}{24} +\frac{1}{120} = \frac{x}{720}\) (4! = 24, 5! = 120)
⇒ \(\frac{5+1}{120}=\frac{x}{720}\)
⇒ \(\frac{6}{120}=\frac{x}{720}\)
⇒ x = 36