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In how many ways can the letters of the word ‘CHEESE’ be arranged?

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Given: We have 6 letters 

To Find: Number of words formed with Letter of the word ‘CHEESE.’ 

The formula used: The number of permutations of n objects, where p1 objects are of one kind, p2 are of the second kind, ..., pk is of a kth kind and the rest if any, are of a different kind is = \(\frac{n!}{p_1!P_2! ......P_k!}\)

Suppose we have these words – C,H,E1,E2,S,E3 

Now if someone makes two words as CHE1E3SE2 and CHE2E3SE1

These two words are different because E1, E2 and E3 are different but we have three similar E’s hence, in our case these arrangements will be a repetition of same words. 

In the word CHEESE, 3 E’s are similar 

∴ n = 6, p1 = 3

\(\frac{6!}{3!}\) = \(\frac{720}{6}\) = 120

In 120 ways the letters of the word ‘CHEESE’ can be arranged.

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