To find: \(\lim\limits_{\text x \to0}\cfrac{sin^24\text x^2}{\text x^4}
\)
\(\lim\limits_{\text x \to0}\cfrac{sin^24\text x^2}{\text x^4}
\)
Therefore,
= 16 × (1)2
= 16
Hence, the value of \(\lim\limits_{\text x \to0}\cfrac{sin^24\text x^2}{\text x^4}
\) = 16