Perimeter of a rhombus = 4a (Here, a is the side of the rhombus)
\(\Rightarrow\) 60 = 4a
\(\Rightarrow\) a = 15 cm
(i) Given:
One of the diagonals is 18 cm long
d1 = 18 cm
Thus, we have:
∴ Length of the other diagonal = 24 cm
(ii) Area of the rhombus = \(\frac{1}{2}d_1\times d_2\)
= \(\frac{1}{2}\times 18\times 24\)
= 216 cm2