Question

Find the area of an equilateral triangle having each side of length 10 cm. (Take √3 = 1.732)

Answer 1

Given: 

Side of the equilateral triangle = 10cm 

Thus we have:

Area of the equilateral triangle = \(\frac{\sqrt{3}}{4}\) side²

= \(\frac{\sqrt{3}}4{}\times 10\times 10\)

= 25 x 1.732

= 43.3 cm²