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Two hydrogen gas balloons having the same pressure and whose volumes are in the ratio of `1:2`, resoectively, are relased simultaneously into air on the surface of the Earth. Find the ratio of time taken to reach a height of 100 m from the ground. (Neglect the air friction)

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`1:1`
`F_("Net")=U-W`
`V_(b)d_(b)a_("Nrt")=V_(b)*d_("air")*g-V_(b)*d_(b)*g`
`a_("Net")=(g(d_("air")-d_(b)))/(d_(b))`
`a_("Net")` is independent of volume of the body. Here the two balloons have same pressure, so their densities will also be equal. Therefore, they take same time to reach the given height.

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