Question

What is the magnitude of the gravitational force between the Earth and a 1kg object on its surface ? (Mass of the earth is `6xx10^(24)` kg and radius of the Earth is `6.4xx10^(6) m)`.

Answer 1

The magnitude of gravitational force is calculated by using the formula : `F=Gxx(m_(1)xxm_(2))/r^(2)`
Now Gravitational constant `G=6.7xx10^(-11)Nm^(2)//Kg^(2)`
Mass of earth `m_(1)=6xx10^(24)kg`
Mass of object `m_(2)=1 kg `
And , Distance between center r=Radius of earth of earth and object
`=6.4 xx 10^(6) m`
Now,Putting these values in the above formula ,we get ` F=(6.7xx10^(-11)xx6xx10^(24)xx1)/((6.4 xx10^(6))^(2)`
or F= 9.8 N
Thus the magnitude of gravitational force between the earth and a 1 kg objective on its surface is 9.8 newtons.