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The volume of 500 g sealed packet is 350 `cm^3`. Will the packet float or sink if the density of water is `1(g)/(cm^3)`? What will be the mass of the water displaced by this packed?

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Here , Mass of packet = 500 g
And Volume of packet `=350 cm,^(3)`
So , Density of packet`=("Mass of pakcet")/("Volume of packet")`
`=(500 g )/(350 cm^(3)`
since the density of packet `(1.42 g cm^(-3))` is more than the density of water `(1g cm ^(-3))`, therfore , the packet will sink in water .
The packet which sinks in water will displace water equal to its own volume .Since the volume of packet is `350 cm ^(3)` of water. We have now to calculate the mass of `350 cm^(2)` of water .
Now , `"Density of water =("Mass of water ")/(Volume of water ")` ltbr gt So, `1g cm^(-3)=("Mass of water ")/(350 cm ^(3))`
And Mass of water `=1 g cm^(-3)xx350 cm^(3))`
=350 g
Thus , the mass of water displaced by the packet is 350 grams.

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