Question

The distance between any two successive antinodes or nodes of a stationary wave is `0.75` m . If the velocity of the wave is `300 m s^(-1)` , find the frequency of the wave .

Answer 1

Wavelength of the waves , `lambda = 0.75 m xx 2 = 1.5` m
Velocity of the wave = `300 m s^(-1)`
frequency , `n = (v)/(lambda) = (300)/(1.5) = 200` hertz