Question

In a wheel and axle, for one complete rotation the magnitude of displacement of effort is 5 times that of the load. What load can be lifted by applying an effort of 10 N? If the radius of the wheel is 35 cm, what is the radius of the axle?

Answer 1

In one rotation,
displacement of effort `= 2 pi R`
displacement of load `= 2 pi r`
given ` 2 pi R = 5 (2 pi r)`
`M.A. = (2piR)/(2 pi r)`
`=(5(2pir))/(2 pi r)`
`:. M.A. = 5 `
Also, M.A. `=(L)/(E)`
`5 = (L)/(10 N)`
` :. L = 50 N`
` R= 35 cm , r = ?`
`5 = (2pi (35))/(2 pi r)`
`:. r = (35)/(5)=7 cm`.