A ball is thrown vertically upwards with a velocity of 49 m//s. Calulate (i) The maximum height to which it rises, (ii) the total time it takes to r

35 views
in Physics
closed
A ball is thrown vertically upwards with a velocity of 49 m//s. Calulate
(i) The maximum height to which it rises,
(ii) the total time it takes to return to the surface of the earth.

by (68.4k points)
selected by

Here, u=49m//s , h=?
total time of ascent + time of descent =t+t=2t=?
At maximum height, finaly velocity,v=0
acceleration =-g=-9.8m//s^(2)
from v^(2)-u^(2)gh, 0-(49)^(2)=2(-9.8)h or h=(49xx49)/(2xx9.8)=122.5m
from v=u+g t, 0=49-9.8t or t=49/9.8=5s
Total time=2t,=10s.