Let the length and the breadth of the park
be 8x metres and 5x metres respectively .
then , area of the park `=(8xxx5x)m^(2)`.
`=(40 x^(2))m^(2)`.
Length of the park including the path `=(8x+3) m.`
Breadth of the park including the path `=(5x+3)m.`
Area of the park including the path `=(8x+3)(5x+3) m^(2)`.
Area of the path `=[(8x+3)(5x+3)-40 x^(2)] m^(2)`
`=(39x+9)= m^(2)`
`therefore 39 +9= 594 implies 39 x= 585 `
` implies x=(585)/(39)=15.`
`therefore ` length `=(8xx15)m = 120 m,`
breadth `=(5xx15) m ` = 75 m.
