We will divide the trapezium into a triangle and a parallelogram
Difference in the lengths of parallel sides = 25 - 11 = 14 cm
We can represent this in the following figure:
Trapezium ABCD is divide into parallelogram AECD and triangle CEB.
Consider triangle CEB.
In triangle CEB, we have,
EB = 25 - 11 = 14 cm
Using Hero’s theorem, we will first evaluate the semi-perimeter of triangle CEB and then evaluate its area
= 84 cm2
Also,
Area of parallelogram AECD = Height x Base = 12 x 11 = 132 cm2
Area of trapezium ABCD = Ar \((\triangle BEC)\) + Ar(parallelogram AECD) = 132 + 84 = 216 cm2