Area of the rhombus = \(\frac{1}{2}\)(Product of diagonals) = \(\frac{1}{2}\)(120 x 44) = 2640 m2
Area of the parallelogram = Base x Height = 66 x Height
Given:
The area of the rhombus is equal to the area of the parallelogram.
Thus, we have
66 x Height = 2640
\(\Rightarrow Height =\frac{2640}{66}=40\,m\)
∴ Corresponding height of the parallelogram = 40 m