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in Geometry by (55.0k points)
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The difference between the two acute angles of a right triangle is \((\frac{\pi}{5})^c\)

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The angle in degree = \(\frac{\pi}{5}\) x \(\frac{180}{\pi}\) = 36° 

Let, two acute angles are x and y 

So, 

ATQ, x - y= 36°......(1) 

x+ y= 90°......(2) 

Solving 1 & 2, we get; 

⇒ 2x= 126° 

⇒ x= 63° 

Putting the value of x in 2, we get; 

⇒ 63°+ y= 90° 

⇒ y= 27° 

So, Two acute angles are 63° & 27°

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