The angle in degree = \(\frac{\pi}{5}\) x \(\frac{180}{\pi}\) = 36°
Let, two acute angles are x and y
So,
ATQ, x - y= 36°......(1)
x+ y= 90°......(2)
Solving 1 & 2, we get;
⇒ 2x= 126°
⇒ x= 63°
Putting the value of x in 2, we get;
⇒ 63°+ y= 90°
⇒ y= 27°
So, Two acute angles are 63° & 27°