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In a circle of diameter 30 cm, the length of a chord is 15 cm. Find the length of the minor arc of the chord.

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: Diameter = 30 cm 

Length of chord = 15 cm 

Radius = 15 cm [r = 0.5 x diameter] 

Since the radius is equal to the length of the chord 

Hence the formed triangle in the circle is an equilateral triangle. 

θ = 60° 

We know that l = r × θ

l = 15 x 60 x π/180 = 5 x π = 5 x 3.14 = 15.7

Therefore, the length of the minor arc is 15.7 cm

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