We have, \(\lim\limits_{\text x \to\pi/3}\cfrac{\sqrt3-tan\,\text x}{\pi-3\text x}
\)
If x → \(\cfrac{\pi}3\), \(\cfrac{\pi}3-\text x\) → 0, π - 3x → 0
Let \(\cfrac{\pi}3\) - x = y then y →0
Hence, \(\lim\limits_{\text x \to\pi/3}\cfrac{\sqrt3-tan\,\text x}{\pi-3\text x}
\) = \(\cfrac43\)