To find: Value of (√3+1)5 - (√3 - 1)5
Formula used: (i)
nCr = \(\frac{n!}{(n-r)!(r)!}\)
⇒ 2[(5)a4 + (10)a2 + (1)]
⇒ 2[5a4 + 10a2 + 1] = (a+1)5 + (a-1)5
Putting the value of a =√3 in the above equation
(√3+1)5 + (√3-1)5 = 2[5(√3)4 + 10(√3)2+ 1]
⇒ 2[(5)(9) + (10)(3) + 1]
⇒ 2[45+30+1]
⇒ 152
