It is required to find the sum (41 + 42 + 43 + …. + 100).
(41 + 42 + 43 + …. + 100) = Sum of integers starting from 1 to 100 – Sum of integers starting from 1 to 40.
Note:
Sum of first n natural numbers, 1 + 2 + 3 +…n,
(41 + 42 + 43 + …. + 100) = Sum of integers starting from 1 to 100 – Sum of integers starting from 1 to 40.
(41 + 42 + 43 + …. + 100) = 5050 – 820 = 4230
