Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
875 views
in Trigonometry by (30.3k points)
closed by

Express each of the following as a product.

1. sin 10x + sin 6x

2. sin 7x – sin 3x

3. cos 7x + cos 5x

4. cos2x – cos 4x

1 Answer

+1 vote
by (29.9k points)
selected by
 
Best answer

= 2sin 9x cos 2x

Using,

sin(A + B) = sinA cosB + cosA sinB

= 2cos\(\frac{10x}{2}sin\frac{4x}{2}\)

= 2cos5x sin2x

Using,

sin( A - B)= sinA cos B - cosA sinB

\(2cos\frac{12x}{2}cos\frac{2x}{2}\)

= 2cos 6x cosx

Using,

cos (A + B) = cosAcosB - sinAsinB

= -2sin\(\frac{6x}{2}\)sin\(\frac{-2x}{2}\)

= 2sin3x sinx

Using,

cos (A - B) = cosAcosB + sinAsinB

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...