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in Geometric Progressions by (15.9k points)

NOTE: In an expression like this ⇒ \(\sum ^n _i = 1 X\) , n represents the upper limit, 1 represents the lower limit , x is the variable expression which we are finding out the sum of and i represents the index of summarization.

(i) \(\displaystyle \sum_{n = 1}^{10}\) (2 + 3n)

(ii) \(\displaystyle \sum_{k = 1}^{n}\) [2k + 3(k - 1)]

(iii) \(\displaystyle \sum_{k = 1}^{n}\) 5n

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1 Answer

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(i) We can write this as (2 + 31 )+(2+32 ) + (2 +33 )+… to 10 terms 

= ( 2+2+2+… to 10 terms) + ( 3+32+33+… to 10 terms) 

= 2×10 + (3+32+33+… to 10 terms) 

= 20 + (3+32+33+… to 10 terms)

Sum of a G.P. series is represented by the formula, Sn = a\(\frac{r^n - 1}{r-1}\), when r≠1. 

‘Sn’ represents the sum of the G.P. series up to nth terms, 

‘a’ represents the first term, 

‘r’ represents the common ratio and 

‘n’ represents the number of terms.

Here, 

a = 3 

r = (ratio between the n term and n-1 term) 3

n = 10 terms

Thus, sum of the given expression is 

= 20 + (3+32+33+… to 10 terms) 

= 20 + 88572 

= 88592

(ii) The given expression can be written as, 

(21 + 31-1 ) + (22 + 32-1 ) + …to n terms 

= (2 + 30 ) + (22+ 31 ) + …to n terms 

= (2 + 1) +(22 + 3 ) + …to n terms

= (2 + 22 + …to \(\frac{n}{2}\) terms) + (1 + 3 + … to \(\frac{n}{2}\) terms)

Sum of a G.P. series is represented by the formula, Sn = a\(\frac{r^n - 1}{r-1}\), when r≠1. 

‘Sn’ represents the sum of the G.P. series up to nth terms, 

‘a’ represents the first term, 

‘r’ represents the common ratio and 

‘n’ represents the number of terms. 

Here, 

a = 2, 1 

r = (ratio between the n term and n-1 term) 2, 3

\(\frac{n}{2}\) terms

(iii) We can rewrite the given expression as 

(51 + 52 + 53+ …to 8 terms)

Sum of a G.P. series is represented by the formula, Sn = a\(\frac{r^n - 1}{r-1}\) , when r>1. 

‘Sn’ represents the sum of the G.P. series up to nth terms, 

‘a’ represents the first term, 

‘r’ represents the common ratio and 

‘n’ represents the number of terms. 

Here, 

a = 5 

r = (ratio between the n term and n-1 term) 5 

n = 8 terms

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